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WHY is 2^-5 used to compute max # half-lives?

Posted by Janelle on April 5, 2002, at 18:09:50

I've got info from two different threads that I've gotta combine here to ask my question so please bear with me. Thanks!

Okay, in one thread it said that no matter what your starting concentration is, after 5 half-lives you are at 1/32 of where you started, which is *effectively* gone.

Under another thread it said that after 5 half-lives there is 2^-5 = 1/32 of the original amount
left. Where does this equation come from? Why is it used - is it an equation that some genius came up with to realize that it takes 5 half lives to effectively eliminate a drug? HELP!


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poster:Janelle thread:101843
URL: http://www.dr-bob.org/babble/20020402/msgs/102057.html