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Re: Well, the answer...

Posted by AuntieMel on January 12, 2007, at 16:36:20

In reply to Anyone good at number theory?, posted by linkadge on January 11, 2007, at 17:17:02

Well, the answer seems to be 2 if both a and b are odd and 1 otherwise (one odd, one even)

It works when plugging numbers into it.

But I keep wanting the answer to be abs|(a - b)|

(a^2 + b^2) factors into (a + b) * (a - b) so it seems if you divide one by the other the remainder is always a - b

I'll pull my number theory book out of mothballs when I get home.

 

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poster:AuntieMel thread:721428
URL: http://www.dr-bob.org/babble/social/20070112/msgs/721736.html